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supernet mask of class c is given 255.255.224.0 .the number of networks that can be joined are

1. 16
2. 32
3. 64
4. none

The supernet id is $255.255.224.0$ .

Here $224->11100000$ Which implies in the supernet mask the first 3 digit is fixed and rest 5 bits can be anything which is $2^{5}=32$ . We can join $32$ network .
I think 32 networks are already joined of class c to make this network.
join means….supernetting
and you are doing subnetting ,why?

I think here they are asking how  much extra 1’s we can use in the network or how much bits we can borrow from the host to make 1’s.

here the given network id is 255.255.224.0.

and as per the standard the subnet mask of class C is 255.255.255.0

224 = 11100000  and 255 = 11111111

thus as we have 5 bits to be included in the network id .

so from 5 bits we can add 2^5 networks  i.e 32 networks.

yeah the questions seems to be poorly framed

@Pranavpurkar which 5bits did you consider? Couldn't understand

224 = 11100000  and 255 = 11111111

thus as we have 5 bits to be included in the network id .

bold zeroes.

@Pranavpurkar why we did not consider the one

edited

@Pranavpurkarwhy you did not consider 111?

you take 1’s from network i’d while subnetting

we have to find out that how many more networks can be added . so 5 bits can be changes to 1 that’s why we have to count those 5 bits.

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