For Burst Mode :-.
For how long would the device tie up the bus when transferring a block of 128 bytes
Bus has requested and release only one time for whole block of data transfer
Bus is tie up with DMA during data transfer to the memory
So total time =Bus request+release+n*cycle time
250+250 +128*500=64500 ns
For Cycle Stealing Mode:-
DMA returns the bus after a word is transfer. The DMA effectively steals cycles
from the processor in order to transfer the byte, so single byte transfer is also known as cycle stealing.
Bus is requested and release for every Byte of transfer So,
total Time= 128*(250+250+500) ==>128000 ns
Can anyone please check this solution