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In a stop and wait ARQ, Bandwidth Delay product is 20,000 bits. Given the frame size is 1000 bits. What is the percentage of utilization of link if we have a protocol that can send 15 frames without waiting for acknowledgement?
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4 Comments

Is it 75% utilisation ?
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Yes, btw what is bandwidth delay product?
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w\o waiting for a ack then it will work like Go-back-n protocol
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@Nisha Bharti it is BW * Round trip delay

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1 Answer

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Bandwidth delay product = $Bw*RTT$; $Bw$ = bandwidth, $RTT = Routed \ Time = 2*Tp$

Here it’s given : $Bw*RTT = 20000\ bits$, and the protocol is sending $15$ frames of size $1000bits$ = $15000bits$

Hence, link utilization or channel utilization or bandwidth utilization or efficiency = $

$(Bits \ successfully \ sent)/ (Bandwidth  \ delay \ product)*100\% $

$= 15000/20000*100 = 75\%$

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