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Using the following illustration, what would be the IP address of E0 if you were using the eighth subnet? The network ID is 192.168.10.0/28 and you need to use the last available IP address in the range. The zero subnet should not be considered valid for this question.

 A. 192.168.10.142 B. 192.168.10.66 C. 192.168.100.254 D. 192.168.10.143 E. 192.168.10.126

Subnet Id of 8th subnet :-  192.168.10.   0111 0000

Broad cast Id of 8th Subnet : 192.168.10.   0111 1111

Last useful ip address for E0 router Interface will be : 192.168.10.   0111 1110 ---->192.126.10.126

So Option D is Correct .

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Edit :

They have mentioned that 0th subnet will not be a  valid subnet so we start from 1

Subnet Id of 8th subnet :-  192.168.10.   1000 0000  (first 4 digit for subnet )

Broad cast Id of 8th Subnet : 192.168.10.   1000 1111

Last useful ip address for E0 router Interface will be : 192.168.10.   1000 1110 ---->192.126.10.142

Option A is correct.

For 8 subnet we have to take 3 bits n?

network ID is 192.168.10.0/28

/28 means 28 bits are fixed for network +subnet  so you have to take initial 4 bits of last octat for subnet.

@lalitver10 for 7th subnet it will be:- 192.168.10.01111111 ?

@Nisha Bharti

then what is the 1st ip for 7th subnet?

7th subnet network id will be:- 192.168.10.0111 0000  non assignable ip address

7th subnet broadcast id will be:- 192.168.10.0111 1111  non assignable ip address

from 192.168.10.0111 0001 to 192.168.10.0111 1110    we have (2^4) -2 ip addresses are assignable.