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Q: In a Gigabit Ethernet LAN the average size of frame is 1000 bytes .If a noise of 2 ms occurs on the LAN , how many frame are destroyed ?

What will happen if Gigabit Ethernet LAN replaced by  a) Fast Ethernet LAN  b) Standard Ethernet LAN  c) 10 Gigabit Ethernet LAN ?

Number of frames destroyed = (data rate of given ethernet  * noice) / average frame size

data rate of,
gigabit ethernet LAN = $1Gbps =$ $10^{9} bps$

Fast Ethernet LAN = $100Mbps$

standard Ethernet LAN = $10Mbps$

so Number of frames destroyed in Gigabit Ethernet LAN = $10^{9} * 2 * 10^{-3} / 8000 = 250$

for other ethernets also you can just change the data rates only.

Note: since the data rate is in bits/sec, we need to convert others in seconds or bits only.

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Number of frames destroyed = (data rate of given ethernet  * noice) / average frame size

can you explain it more?

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