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41 votes
41 votes

A company has a class $C$ network address of $204.204.204.0$. It wishes to have three subnets, one with $100$ hosts and two with $50$ hosts each. Which one of the following options represents a feasible set of subnet address/subnet mask pairs?

  1. $204.204.204.128/255.255.255.192$
    $204.204.204.0/255.255.255.128$
    $204.204.204.64/255.255.255.128$
  2. $204.204.204.0/255.255.255.192$
    $204.204.204.192/255.255.255.128$
    $204.204.204.64/255.255.255.128$
  3. $204.204.204.128/255.255.255.128$
    $204.204.204.192/255.255.255.192$
    $204.204.204.224/255.255.255.192$
  4. $204.204.204.128/255.255.255.128$
    $204.204.204.64/255.255.255.192$
    $204.204.204.0/255.255.255.192$
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6 Answers

7 votes
7 votes

MSB in last 8 bits is in use to get subnet since it is class c ip

10000000 / 128(mask)subnet id bit(10) --->subnet1 ( since need 100 host so we assign max 128 here so 28 gone waste).
01000000/192( mask) subnet id bit(01)--->subnet2 ( since need 50 host so we assign max 64 here so 14 gone waste). here we can go for option c b/c we get coolision of ip address since subnet 1 also have 11000000 and subnet 2 also . so here D is answer
00000000 /192( mask)subnet id bit(00)--->subnet2(0)  ( since need 50 host so we assign max 64 here so 14 gone waste).

D is answer.

6 votes
6 votes

I have drawn two possible cases here

Case 2 is our answer which is option D

 

Answer:

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