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Given answer 

7th = 30

8th = c

 

How??

 

1 Answer

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8.

no of  cable connected to the host = 90  which contain 2^7 no of bit which is fixed   {2^6 < 90 so took 2^7}

as given it is class B address  so    255.255.xxxxxxxx.xxxxxxxx

255.255.11111110.0000000   {in 3rd octant 7 bit fixed for subnet)   now highlight bit use for host

which contain 2^9 bit = 512  but in this   address which is all zero {network address} and last address all 1’s which is broadcast add.

 so after removing them 512-2  = 510

 

 

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