Please Note: Please consider Node E in the image as Node F(There was labelling mistake in diagram).
Below is the image showing vector exchanges over a short period of time from which we will calculate what is the distance from F to A.
As, you can see, after every two instance of time, the distance to A from F is getting increased by 2.
By observation I have tried to deduce a formula to compute value to get to A from F at t+100.
I divided the 10 time slots into 5 stages with each stage showing 2 vector exchanges.
At time t which belongs to Stage S,
The value will be given by 3+2*(S-1).
For example at t=t+5, Stage S will be given by ceil(5/2)=3
Value=3+2*(3-1) = 3+4=7 this is the distance from F to reach A.
Similarly to calculate at t+100,
Stage number = ceil(100/2)=50
Value = 3+2*(50-1) = 3+98=101
This will be the distance from F to reach A at time instant t+100.
So, answer is option A.