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The given codeword is represented in hexadecimal format as $0x$ as a prefix. Perform the EXOR operations between 2 codewords, the number of $1’s$ in the resultant code word is called hamming distance.

$(0XAA)_H=1010  1010$

$\oplus$

$(0X55)_H= 0101  0101$


                      $(11111111)$

So the hamming distance of the given codeword is $8$

Ref: UGC NET CSE | June 2014

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:8

Apply XOR

0xAA = 1010 1010
0x55 = 0101 0101
----------------
0xFF = 1111 1111

 In the resultant code, the number of 1′s shows Hamming Distance

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Karthik Akula asked Sep 1, 2016
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Can anyone explain me how to detect and correct errors using hamming code ?