Based on the following passage, answer the Questions :
A $3000 \mathrm{~km}$ long trunk operates at $1.536 \mathrm{mbps}$ and is used to transmit 64 bytes frames and uses sliding window protocol. The propagation speed is $6 \mu \mathrm{sec} / \mathrm{km}$.
The transmission and propagation delays are respectively
- $\mathrm{T}_{\mathrm{t}}=333.33 \mu \mathrm{sec}, \mathrm{T}_{\mathrm{p}}=18000 \mu \mathrm{sec}$
- $T_{t}=300 \mu \mathrm{sec}, T_{p}=15360 \mu \mathrm{sec}$
- $\mathrm{T}_{\mathrm{t}}=33.33 \mu \mathrm{sec}, \mathrm{T}_{\mathrm{p}}=1800 \mu \mathrm{sec}$
- $T_{\mathrm{t}}=1800 \mu \mathrm{sec}, T_{\mathrm{P}}=33.33 \mu \mathrm{sec}$