Match List I with List II :
$\begin{array}{ll}
\text{List I} & \text{List II} \\ \\
\text {(A) BCNF } & \text { (I) It removes multivalued dependency } \\
\text {(B) 3} \mathrm{NF} & \text { (II) It is not always dependency preserving } \\
\text {(C) 2} \mathrm{NF} & \text{ (III) It removes transitive dependency} \\
\text {(D) 4} \mathrm{NF} & \text { (IV) It removes partial functional dependency }\end{array}$
Choose the correct answer from the options given below:
- $\text{(A)-(III), (B)-(II), (C)-(IV), (D)-(I)}$
- $\text{(A)-(II), (B)-(IV), (C)-(I), (D)-(III)}$
- $\text{(A)-(II), (B)-(III), (C)-(IV), (D)-(I)}$
- $\text{(A)-(II), (B)-(I), (C)-(IV), (D)-(III)}$
