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If $N = 888 $ up to $100$ digits, what is the remainder when $N$ is divided by $625?$

  1. 128
  2. 138
  3. 338
  4. 388
asked in Numerical Ability by Active (2.9k points)
edited by | 2.6k views

1 Answer

+4 votes
Best answer
$625 \times 16 = 10000$
i.e. anything which is multiple of 10000 will also be multiple of 625

$\underbrace{8888 \cdots 8}_{\text{100 times}} =\underbrace{8888 \cdots 8}_{\text{96 times}} \times 10000 +8888$

So to find reminder of $\underbrace{88888888888888\cdots 8}_{\text{100 times}}$, just find Reminder when 8888 is divided by 625

$8888 = 625 \times 14 + 138$
So, 138 is reminder.
answered by Veteran (59.9k points)
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o.O So for any such qn, we can use this method? If suppose the digits were not repeating, then also same method?

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