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Assume an instruction set that uses a fixed 31 bit instruction length. Operand specifies are 4 bits in length. If there are m-three operand instructions in total, then how many two instructions are possible at maximum?

I believe they mean opcode by that .

Yes @Kabir5454 Otherwise Opcode comes out to be $19 bits$ which does not match the options

here operand specifies means opcode

Ans:(2^19  -m)*2^4

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