0 votes 0 votes If big oh is possible for an algorithm but big Omega is not,then is it small o? Algorithms algorithms asymptotic-notation + – nbhatt asked Nov 3, 2022 nbhatt 284 views answer comment Share Follow See 1 comment See all 1 1 comment reply nishantsharma commented Jan 11, 2023 reply Follow Share No it is not like that. Big Oh means greater than or equal to while big Omega means smaller the or equal to. Small means greater than but not equal to. If it is big Oh it simply means it is greater or it may be equal hence no small oh. 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes small oh ($o$) means it is Non Tighest upper bound. If only Big oh($O$) exist and theta($\Theta$) don’t , it doesn’t mean that Big omega($\Omega$) doesn’t exist . it’s just that both $O$ and $\Omega$ aren’t same. Pranavpurkar answered Nov 3, 2022 Pranavpurkar comment Share Follow See all 0 reply Please log in or register to add a comment.