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If big oh is possible for an algorithm but big Omega is not,then is it small o?

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small oh ($o$) means it is Non Tighest upper bound.

If only Big oh($O$) exist and theta($\Theta$) don’t  , it doesn’t mean that Big omega($\Omega$) doesn’t exist . it’s just that both $O$ and $\Omega$  aren’t same.

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