0 votes 0 votes Regular Expression for accepting the language L = { 0^n1^m | n+m=even } I got this solution – (00)*(11)*+0(00)*1(11)* please point out how this – {(00)* (01)* (11)* } RE differs from the above one Theory of Computation theory-of-computation regular-expression + – Dknights asked Nov 9, 2022 • retagged Nov 9, 2022 by makhdoom ghaya Dknights 370 views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply jugnu1337 commented Nov 9, 2022 reply Follow Share @Dknights i think 010101…. accept by 2nd expression while 1st on didn't 1 votes 1 votes Chandrabhan Vishwa 1 commented Nov 9, 2022 reply Follow Share @jugnu1337 yes 0 votes 0 votes Please log in or register to add a comment.