0 votes 0 votes Assume 10 Mbps Ethernet and two stations A and B on it’s same segment. The RTT between two nodes is 650 bit times. A and B start transmitting frame and collision occurs and both sends 30-bit jam signal. Find the time at which both nodes A and B sense an idle channel (in μsec). sushma singh asked Jan 31, 2016 sushma singh 461 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes 225 bit to go from A to B. let just before B der is collision. 50 bit jamming signal. so it will take 225+50 bit to reach A. Total time = 225 + 50 + 225 = 500 bit time. Time in second = 500/10M = 50 micro second Digvijay Pandey answered Feb 1, 2016 Digvijay Pandey comment Share Follow See all 2 Comments See all 2 2 Comments reply papesh commented Apr 14, 2016 reply Follow Share is it 325 or 225 ?? 0 votes 0 votes arch commented Nov 17, 2017 reply Follow Share @ Digvijay Pandey sir i think propagation delay should be 325. and sir i dont undersatnd propagation delay again added. after adding (propagation delay + jamming signal) reach A then station is ideal why you add again propagation delay. what i am missing here? 0 votes 0 votes Please log in or register to add a comment.