Please explain

## 2 Answers

**(B) **is the answer. $\text{IEEE 754}$ representation uses normalized representation when the exponent bits are all non zeroes and hence an implicit '1' is used before the decimal point. So, if mantissa is:

$0000 \dots 0$

Ut would be treated as:

$1.000 \ldots 0$

and hence, the exponent need to be $-1$ for us to get $0.1$ which is the binary representation of $0.5.$

More into IEEE floating point representation:

http://steve.hollasch.net/cgindex/coding/ieeefloat.html

### 7 Comments

In IEEE biasing of exponent is must.

Step 1: decimal 0.5 --> binary 0.1

Step 2: normalize binary 0.1 --> 1.0 * 2^{-1}

Step 3: exponent -1 + 127 = 126 = binary 01111110

Step 4: remove hidden digit from 1.0 --> 0 (1 is implicit in IEEE representation)

Step 5: 0.5 is positive - the sign bit is zero: 0

The next eight bits are the exponent: 01111110

The next 23 bits are the mantissa: 000000000000000000000

Binary result (32 bits): 10111111000000000000000000000000

I think there is something wrong with the question. Arjun Sir, please explain.