Ace academy handout

Question

Please solve and explain this question, like explaining to a 2nd-grade student. Answer is 128 KB, for verification.

Answer 1

$page$ $table$ $size$ $=$ $\frac{LAS}{page size} *PTE_{size}$

Here, LAS = logical address space = $2^{LA_{bits}}$ = $2^{32}$

Let, page size = $2^x$  and PTE size is given as $32$ $bits$($2^2$ B)

Here it is asked the size of page(in Bytes) such that page table exactly fits in one page frame,

i.e (Page table size=frame size = page size = $2^x$)

Now,

$page$ $table$ $size$ $=$ $\frac{LAS}{page size} * PTE_{size}$

$2^x$ = $\frac{2^{32}}{2^x} * 2^2$

after solving this we will get $x$ $=$ $17$ $bits$

Thus , page size = $2^{17}B$ = $128$ $KB$.