1 votes 1 votes How to do this Boolean multiplication? And which Boolean law is applicable here ? ( P' + Q ) ( Q' + P ) Mathematical Logic self-doubt digital-logic boolean-algebra + – dutta18 asked Dec 9, 2022 • retagged Dec 9, 2022 by makhdoom ghaya dutta18 360 views answer comment Share Follow See 1 comment See all 1 1 comment reply Shoto commented Dec 9, 2022 reply Follow Share Use distributive property $(P’+Q)(Q’+P) = P’Q’ + P’P + QQ’ +QP = P’Q’ + PQ$ 1 votes 1 votes Please log in or register to add a comment.
Best answer 3 votes 3 votes $( P' + Q ) ( Q' + P )$ $(P'Q' + P'P + QQ' + QP )$ $(P'Q' + QP )$ $[ P'P = QQ' = 0]$ This is nothing but the $EXNOR$ operation. $(P \odot Q )$ Pranavpurkar answered Dec 9, 2022 • selected Dec 9, 2022 by dutta18 Pranavpurkar comment Share Follow See all 0 reply Please log in or register to add a comment.