0 votes 0 votes In synchronous transmission, 5 eight bit characters are included in 30 eight bit information characters. If bit rate of sender is 4200 bits/sec, what is the bit rate of receiver (in bits per sec)? Computer Networks made-easy-test-series computer-networks network-communication + – Akanksha Kesarwani asked Feb 2, 2016 • edited Mar 5, 2019 by akash.dinkar12 Akanksha Kesarwani 615 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Time required for sending = 240 bits / 4200 bits/sec = 24/420 sec Time required for receiving = 35*8 bits / receiver rate Equate both and get the answer. nikhil1008 answered Mar 24, 2016 nikhil1008 comment Share Follow See all 0 reply Please log in or register to add a comment.
