1 votes 1 votes Why is it 416 ? Computer Networks ace-test-series computer-networks ip-addressing fragmentation + – Nikita Moghe asked Feb 2, 2016 • edited Mar 6, 2019 by akash.dinkar12 Nikita Moghe 1.0k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 5 votes 5 votes Mtu is 440 Ip header =20 So 420 bytes still there for data Amount of data in fragment should be divisible by 8 420 not divisible by 8 so we take 416 Pooja Palod answered Feb 2, 2016 • selected Feb 3, 2016 by Nikita Moghe Pooja Palod comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes MTU is given as 440 ,so data that can be sent in each fragment is 440 - 20 = 420 . but 420/8 is not a whole number so we will take other least multiple just lesser than 420 which comes to be 416 . the fragments will be fragment size offset 416 0 416 52 416 104 219 156 garima answered Apr 27, 2017 garima comment Share Follow See all 0 reply Please log in or register to add a comment.
–1 votes –1 votes Ans should be 165, mtu=440(given),(which is divisible by 8) Ip packet containing 1500 byte data,so 1480(payload)+20(IP header) 420+20 420+20 420+20 220+20, So last frame offset is 1320/8=165 Rinky Parmar answered Nov 4, 2016 Rinky Parmar comment Share Follow See 1 comment See all 1 1 comment reply Aboveallplayer commented Nov 4, 2016 reply Follow Share wrong approach!! in mtu also there has to be 20 byte header 0 votes 0 votes Please log in or register to add a comment.