retagged by
496 views

1 Answer

Best answer
4 votes
4 votes
L = { e, 0, 0000, 000000000}.

L* = ( e + 0 + 0000 + 000000000)*

     = ( e + 0 + 0000 + 000000000)( e + 0 + 0000 + 000000000)( e + 0 + 0000 + 000000000)….

     = (e, 0, 00, 000, 0000, 00000,…….) {use e and 0 from each grouping to generate this}

     = 0*

Hence L is an RL.

Note: (Shorter and faster way to solve the sum as mentioned by @raja11sep)

Every finite language is regular.

Regular languages are closed under Kleene closure.
edited by

Related questions