when it is option C the control will continue to iterate as $i=8$ and $j=9$;
again and again $i$ will be assigned $k$ which itself equals $8$ as $\frac{8+9}{2}$ being stored in an integer type variable, will evaluate to $8$.
For option A, with $x=9, k$ will take the following values:
- $4$
- $6$
- $7$
- $8 - y[8] = 9, x$ found
For option D, with $x=10, k$ will take the following values: