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Operators $\square,\Diamond$ and $\rightarrow$ are defined by: $a\,\square\,b=\frac{a-b}{a+b};\, a\,\Diamond\; b=\frac{a+b}{a-b};$ $a\,\rightarrow\, b=ab.$

Find the value of $(66\,\square\, 6)\rightarrow(66\,\Diamond\; 6).$

  1. $-2$
  2. $-1$
  3. $1$
  4. $2$
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$\require {cancel}(66\,\square\, 6)\rightarrow(66\,\Diamond\; 6) = \frac{\cancel{66-6}}{\cancel{66+6}} \times \frac{\cancel{66+6}}{\cancel{66-6}} = 1.$
Answer:

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