4 votes 4 votes Operators $\square,\Diamond$ and $\rightarrow$ are defined by: $a\,\square\,b=\frac{a-b}{a+b};\, a\,\Diamond\; b=\frac{a+b}{a-b};$ $a\,\rightarrow\, b=ab.$ Find the value of $(66\,\square\, 6)\rightarrow(66\,\Diamond\; 6).$ $-2$ $-1$ $1$ $2$ Analytical Aptitude gate2015-ec-1 logical-reasoning easy + – Akash Kanase asked Feb 12, 2016 retagged Dec 19, 2023 by Hira Thakur Akash Kanase 1.4k views answer comment Share Follow See 1 comment See all 1 1 comment reply amit166 commented Oct 11, 2019 reply Follow Share independent for value of real value of a and b answer =1 0 votes 0 votes Please log in or register to add a comment.
Best answer 4 votes 4 votes $\require {cancel}(66\,\square\, 6)\rightarrow(66\,\Diamond\; 6) = \frac{\cancel{66-6}}{\cancel{66+6}} \times \frac{\cancel{66+6}}{\cancel{66-6}} = 1.$ Arjun answered Jun 1, 2019 Arjun comment Share Follow See 1 comment See all 1 1 comment reply Lakshman Bhaiya commented Jan 3, 2020 reply Follow Share If they asked find the value of $(P\,\square\, Q)\rightarrow(P\,\Diamond\; Q)?$ Then $(P\,\square\, Q)\rightarrow(P\,\Diamond\; Q) = \dfrac{P-Q}{P+Q} \times \dfrac{P+Q}{P-Q} = 1$ 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes option C as (60/52)*(52/60)=1 saipriyab answered Oct 15, 2017 saipriyab comment Share Follow See all 0 reply Please log in or register to add a comment.