Why and what is the use of the tree.

6 votes

A tiger is $50$ leaps of its own behind a tree. The tiger takes $5$ leaps per minute to the deer's $4.$ If the tiger and the deer cover $8$ meter and $5$ meter per leap respectively, what distance in meters will the tiger have to run before it catches the deer$?$

- 🚩 Edit necessary | 👮 reboot | 💬 “it is "behind a deer" and not tree”

7 votes

Best answer

1 vote

Tiger (runs) --> Deer (runs) --->

**Tiger**----------------------------------------**Tree**--------------------------**Tiger catch Deer (here)**

|---------------------50 Leaps --------------|-------------x m-----------|

50*8 = 400 m .

|--------------------------------------------400 + x -------------------------|

Tiger(speed)=8*5=40m/s

Deer(speed)=5*4=20m/s

after t time tiger catch deer

t=(400+x) / 40 (tiger)

t=x / 20 (deer)

(400+x) / 40 = x/20

x=400

total time to catch deer = 400+x

= 400 + 400

= **800** m