1 votes 1 votes L1 = a*b* , L2 = a^+ b^+ . L2-L1 = ? Theory of Computation theory-of-computation regular-expression + – mo7ammedfarooq asked Jan 16, 2023 • retagged Jan 16, 2023 by makhdoom ghaya mo7ammedfarooq 375 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply Sunnidhya Roy commented Jan 16, 2023 reply Follow Share L1 - L2 = a* + b* ?? L2 - L1 = phi ?? 0 votes 0 votes mo7ammedfarooq commented Jan 16, 2023 reply Follow Share yeah but can you explain me how it is phi and not epsilon because in L1 we get epsilon too right? 0 votes 0 votes Sunnidhya Roy commented Jan 16, 2023 reply Follow Share Is L2 generating epsilon? 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes It is quite straightforward. rhl answered Jul 6, 2023 rhl comment Share Follow See all 0 reply Please log in or register to add a comment.
