Question

consider 16tb disk that uses 4kb block and free list method. how many block address can be stored in a block

Comments

here 16 TB disk means   16*2^40 =2^44 byte data =>2^44/2^12=2^32block  means 32 bit =4 byte

hence 1024  (address )4byte address  stored in  one block

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Thank you so much

Answer 1

Disk size = $16TB$

Block size = $4KB$

Blocks = Total disk size / Block size =$\frac{16TB}{4KB}$ = $4G$

Hence address size = $\log 4G$ = $32$ bits = $4 B$

Maximum number of address a block can hold = $\frac{4KB}{4B}$ = $1K$ = $1024$

Comments

Thank you so much