0 votes 0 votes Operating System operating-system addressing-modes + – Shubham Kathiriya asked Jan 26, 2023 • retagged Jan 26, 2023 by makhdoom ghaya Shubham Kathiriya 606 views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply Chandrabhan Vishwa 1 commented Jan 26, 2023 i edited by Chandrabhan Vishwa 1 Jan 26, 2023 reply Follow Share here 16 TB disk means 16*2^40 =2^44 byte data =>2^44/2^12=2^32block means 32 bit =4 byte hence 1024 (address )4byte address stored in one block 1 votes 1 votes Shubham Kathiriya commented Jan 27, 2023 reply Follow Share Thank you so much 0 votes 0 votes Please log in or register to add a comment.
3 votes 3 votes Disk size = $16TB$ Block size = $4KB$ Blocks = Total disk size / Block size =$\frac{16TB}{4KB}$ = $4G$ Hence address size = $\log 4G$ = $32$ bits = $4 B$ Maximum number of address a block can hold = $\frac{4KB}{4B}$ = $1K$ = $1024$ Shubhodeep answered Jan 26, 2023 Shubhodeep comment Share Follow See 1 comment See all 1 1 comment reply Shubham Kathiriya commented Jan 27, 2023 reply Follow Share Thank you so much 0 votes 0 votes Please log in or register to add a comment.