it is given that $f_{n+1}=f_n+f_{n-1}$
if we put $n=6,5,4,3,2$ we get our value.
put $n=6\rightarrow f_7=f_6+f_5\implies f_5=60-37=23$
put $n=5\rightarrow f_6=f_5+f_4\implies f_4=37-23=14$
put $n=4\rightarrow f_5=f_4+f_3\implies f_3=23-14=9$
put $n=3\rightarrow f_4=f_3+f_2\implies f_2=14-9=5$
put $n=2\rightarrow f_3=f_2+f_1\implies f_1=9-5=4$
So we get $f_1=4$ option $(B)$ is correct.