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$\text{A}$ can complete a piece of work in $4$ days. $\text{B}$ takes double the time taken by $\text{A, C}$ takes double that of $\text{B},$ and $\text{D}$ takes double that of $\text{C}$ to complete the same task. They are paired in groups of two each. One pair takes two-thirds the time needed by the second pair to complete the work. Which is the first pair?

  1. $\text{A, B}$
  2. $\text{A, C}$
  3. $\text{B, C}$
  4. $\text{A, D}$
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A’s 1-day work is 1/4

B’s 1-day work is 1/8

C’s 1-day work is 1/16

D’s 1-day work is 1/32

(B+C)’s 1-day work is 1/8+1/16 = 3/16

(A+D)’s 1-day work is 1/4+1/32 = 9/32

So, A+D complete in 32/9 day= 2/3 (B+D complete in 16/3)

So, A, D is the answer. Option D.
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