edited by
1,032 views
16 votes
16 votes

Suppose that we are solving $A x=\left(\begin{array}{l}1 \\ 2 \\ 3\end{array}\right)$

In each of the option below, a complete solution $x$ is proposed.

Which of the following could possibly be the solution for above system of linear equations?

  1. $\vec{x}=\left(\begin{array}{l}
    1 \\
    2 \\
    3 \\
    4
    \end{array}\right)$
  2. $\vec{x}=\left(\begin{array}{l}1 \\ 2 \\ 3 \\ 4\end{array}\right)+\alpha_1\left(\begin{array}{c}1 \\ -1 \\ 5 \\ 17\end{array}\right)+\alpha_2\left(\begin{array}{l}1 \\ 0 \\ 0 \\ 1\end{array}\right)$ for all real numbers $\alpha_1, \alpha_2 \in \mathbb{R}$
  3. $\vec{x}=\left(\begin{array}{l}1 \\ 2\end{array}\right)+\alpha\left(\begin{array}{l}1 \\ 2\end{array}\right)$ for all real numbers $\alpha \in \mathbb{R}$
  4. $\vec{x}=\left(\begin{array}{l}1 \\ 2\end{array}\right)+\alpha\left(\begin{array}{c}1 \\ -1\end{array}\right)$ for all real numbers $\alpha \in \mathbb{R}$
edited by

1 Answer

14 votes
14 votes
B, D.

Option A)

The dimension of x and b gives the dimension of matrix A.

For this option, the Dimension of matrix A must be 3 * 4.

Since the number of rows is less than the number of columns, the matrix may have zero solutions OR infinite solutions.

Option A is just a single solution, Therefore It is false.

Option B)
From the similar reasoning above, option B is a possible solution since it is infinite solution for Ax = $\begin{bmatrix} 1\\ 2\\ 3 \end{bmatrix}$.

Option C)

For this option, the dimension of the matrix must be 3 * 2.

In the complete solution, it is given that $\begin{bmatrix} 1\\ 2\end{bmatrix}$ solves Ax = $\begin{bmatrix} 1\\ 2\\ 3 \end{bmatrix}$.

It is also given that  $\begin{bmatrix} 1\\ 2\end{bmatrix}$  solves Ax = 0. It is a contradiction and therefore, option C is false.

Option D)

From the similar reasoning of option C, it is possible for option D to be true.
edited by
Answer:

Related questions