5 votes 5 votes Let $F$ and $G$ be two propositional formula. Which of the following is/are True? $F \vee G$ is a tautology iff at least one of them is a tautology If $F \rightarrow G$ is a tautology and $F$ is a tautology, then $G$ is a tautology. $(F \rightarrow G) \vee (F \rightarrow \neg G)$ is a tautology. $(F \rightarrow G) \wedge (F \rightarrow \neg G)$ is a tautology iff $F$ is a contradiction. Mathematical Logic goclasses2024_wq7 goclasses mathematical-logic propositional-logic multiple-selects 2-marks + – GO Classes asked Apr 5, 2023 edited Apr 5, 2023 by Lakshman Bhaiya GO Classes 601 views answer comment Share Follow See 1 comment See all 1 1 comment reply Deepak Poonia commented Apr 6, 2023 reply Follow Share Find the detailed answer HERE. 1 votes 1 votes Please log in or register to add a comment.
2 votes 2 votes here answer should be ABCD but given is BCD A because FVQ so if atleast one of them is true then output is true .. JayRathi answered Apr 6, 2023 JayRathi comment Share Follow See all 8 Comments See all 8 8 Comments reply Show 5 previous comments Abhrajyoti00 commented Apr 6, 2023 reply Follow Share So if you take q = True, ~q has to be False right? 0 votes 0 votes Deepak Poonia commented Apr 6, 2023 reply Follow Share Find the detailed answer HERE. 1 votes 1 votes Silver_Reaper commented Oct 25, 2023 reply Follow Share @Suraj Reddy So the reason option A is wrong is because it is mentioned as iff(if and only if) in the option.So in case the option had mentioned ‘if’ instead of ‘iff’,then option A would have been correct as well right? 1 votes 1 votes Please log in or register to add a comment.