38 votes 38 votes In the IEEE floating point representation the hexadecimal value $0\text{x}00000000$ corresponds to The normalized value $2^{-127}$ The normalized value $2^{-126}$ The normalized value $+0$ The special value $+0$ Digital Logic gatecse-2008 digital-logic floating-point-representation ieee-representation easy + – Kathleen asked Sep 11, 2014 Kathleen 12.7k views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply Rajesh Panwar commented Dec 15, 2018 reply Follow Share what is the difference between Option A and D 0 votes 0 votes Veenit commented Sep 17, 2019 reply Follow Share The prefix ‘0x’ shows it’s a hexadecimal constant, in case anyone is unaware of 0x usage. 7 votes 7 votes ShouvikSVK commented Jan 3, 2022 reply Follow Share The entire list: 1 votes 1 votes JAINchiNMay commented Nov 14, 2022 reply Follow Share What is SNAN , QNAN 1 votes 1 votes Please log in or register to add a comment.
Best answer 57 votes 57 votes $$\begin{array}{|c|c|c|}\hline \textbf{S} & \textbf{BE} & \textbf{M} & \textbf{Value} \\\hline 0/1 & {\color{Magenta} {\text{All 0’s}}} & {\color{Magenta} {\text{All 0’s}}} & 0 \\\hline 0 & {\color{Blue} {\text{All 1’s}}} & {\color{Magenta} {\text{All 0’s}}} & +\infty \\\hline 1 & {\color{Blue} {\text{All 1’s}}} & {\color{Magenta} {\text{All 0’s}}} & -\infty \\\hline 0/1 & {\color{Blue} {\text{All 1’s}}} & \text{Non-zero}& \text{NaN} \\\hline\end{array}$$The answer is option D. Reference: http://steve.hollasch.net/cgindex/coding/ieeefloat.html amarVashishth answered Nov 8, 2015 edited May 2, 2021 by Lakshman Bhaiya amarVashishth comment Share Follow See all 2 Comments See all 2 2 Comments reply rajatmyname commented May 7, 2019 reply Follow Share Sir, what is the difference between option C and option D? 2 votes 2 votes Raju Kalagoni commented Jan 29, 2020 reply Follow Share earlier to IEEE 758 representation, floating numbers couldn't differentiate -0 and +0. So, they come up with IEEE 758 floating poing representation in 32 bit and 64 bit and they marked +0 and -0 representation special that's all I read somewhere, don't know exact history. 1 votes 1 votes Please log in or register to add a comment.
16 votes 16 votes D. The special value +0. Ref: http://steve.hollasch.net/cgindex/coding/ieeefloat.html Arjun answered Jun 8, 2015 Arjun comment Share Follow See all 5 Comments See all 5 5 Comments reply 2018 commented Dec 14, 2016 reply Follow Share sir why not A?? this 32 bit ieee representation also correspond to normalize 2^(-127) using bias=(2^(8-1))-1 value= (-1)^0 * 1.(23 0's) * 2^(0-bias)=1*2^(-127) 1 implicit here and not stored. @arjun sir plz reply 0 votes 0 votes 2018 commented Dec 14, 2016 reply Follow Share srry got the point, we can't take all zero in exponent part in case of ieee 754 single precision, min value that can be stored is 2^(-126), which in case of when exponent field contain 1 in LSB position and all zero in mantissa part, so given format reserved for special value/ thanks 5 votes 5 votes Sandeep Suri commented Jan 13, 2017 reply Follow Share Answer is not A because Exponent and Mantisa both are zero which is equal to special value +0. 0 votes 0 votes krishn.jh commented Mar 27, 2018 reply Follow Share Very Nice and useful link it clears all IEEE Floating Point Representation Doubts. Thank you Sir!. 1 votes 1 votes Mk Utkarsh commented Aug 3, 2018 reply Follow Share Answer is not A because range of single precision normalized form is $\pm 2^{-126}$ to $\left (2 -2^{(-23)} \right ) \times 2 ^{127}$ 0 votes 0 votes Please log in or register to add a comment.