what is the difference between Option A and D

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+27 votes

In the IEEE floating point representation the hexadecimal value $0\text{x}00000000$ corresponds to

- The normalized value $2^{-127}$
- The normalized value $2^{-126}$
- The normalized value $+0$
- The special value $+0$

+42 votes

Best answer

Answer is **option D.**

**Reference: **http://steve.hollasch.net/cgindex/coding/ieeefloat.html

+13 votes

D. The special value +0.

Ref: http://steve.hollasch.net/cgindex/coding/ieeefloat.html

0

sir why not A??

this 32 bit ieee representation also correspond to normalize 2^(-127)

using bias=(2^(8-1))-1 value= (-1)^0 * 1.(23 0's) * 2^(0-bias)=1*2^(-127)

1 implicit here and not stored. @arjun sir plz reply

this 32 bit ieee representation also correspond to normalize 2^(-127)

using bias=(2^(8-1))-1 value= (-1)^0 * 1.(23 0's) * 2^(0-bias)=1*2^(-127)

1 implicit here and not stored. @arjun sir plz reply

+2

srry got the point, we can't take all zero in exponent part in case of ieee 754 single precision, min value that can be stored is 2^(-126), which in case of when exponent field contain 1 in LSB position and all zero in mantissa part, so given format reserved for special value/ thanks

+1

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