in Quantitative Aptitude
10 votes
10 votes

If $m$ students require a total of $m$ pages of stationery in $m$ days, then $100$ students will require $100$ pages of stationery in

  1. $100$ days
  2. $m /100$ days
  3. $100/m$ days
  4. $m$ days
in Quantitative Aptitude

2 Answers

12 votes
12 votes
Best answer

Ans should be D)

as we know Men and days are inversely proportional and work and days are directly proportional 

so we can write  $\dfrac{M_1D_1}{W_1} =\dfrac{M_2D_2}{W_2}$

According to given data in question 

$\dfrac{m\times m}{m}=\dfrac{100\times D_2}{100}$ 

$D_2 = m$ days 

selected by
4 votes
4 votes

This can be solved by unitary method.

m students-------------------> m pages -----------------> in m days

m students--------------------> m/m pages/day=1 page/day

1 student  ---------> 1/m page/day

100 students= 100/m pages/day

GIVEN : 100 students will require 100 pages.

1 day -----------> 100/m pages by      100 students

x days--------------> 100 pages by       100 students.

solve for x by cross multiplication.  x=m days .

hence, option D is correct


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