If $m$ students require a total of $m$ pages of stationery in $m$ days, then $100$ students will require $100$ pages of stationery in
Ans should be D)
as we know Men and days are inversely proportional and work and days are directly proportional
so we can write $\dfrac{M_1D_1}{W_1} =\dfrac{M_2D_2}{W_2}$
According to given data in question
$\dfrac{m\times m}{m}=\dfrac{100\times D_2}{100}$
$D_2 = m$ days
This can be solved by unitary method.
m students-------------------> m pages -----------------> in m days
m students--------------------> m/m pages/day=1 page/day
1 student ---------> 1/m page/day
100 students= 100/m pages/day
GIVEN : 100 students will require 100 pages.
1 day -----------> 100/m pages by 100 students
x days--------------> 100 pages by 100 students.
solve for x by cross multiplication. x=m days .
hence, option D is correct