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Akash Kanase
asked
in Quantitative Aptitude
Feb 16, 2016

2,014 views
4 votes

**This can be solved by unitary method.**

m students-------------------> m pages -----------------> in m days

m students--------------------> m/m pages/day=1 page/day

1 student ---------> 1/m page/day

100 students= 100/m pages/day

**GIVEN : 100 students will require 100 pages.**

1 day -----------> 100/m pages by 100 students

x days--------------> 100 pages by 100 students.

solve for x by cross multiplication. x=m days .

**hence, option D is correct**