6 votes

If $m$ students require a total of $m$ pages of stationery in $m$ days, then $100$ students will require $100$ pages of stationery in

- $100$ days
- $m /100$ days
- $100/m$ days
- $m$ days

10 votes

Best answer

2 votes

**This can be solved by unitary method.**

m students-------------------> m pages -----------------> in m days

m students--------------------> m/m pages/day=1 page/day

1 student ---------> 1/m page/day

100 students= 100/m pages/day

**GIVEN : 100 students will require 100 pages.**

1 day -----------> 100/m pages by 100 students

x days--------------> 100 pages by 100 students.

solve for x by cross multiplication. x=m days .

**hence, option D is correct**