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Two points $(4, p)$ and $(0, q)$ lie on a straight line having a slope of $3/4$. The value of $( p – q)$ is

  1. $-3$
  2. $0$
  3. $3$
  4. $4$
in Numerical Ability by Boss (41.9k points)
edited by | 334 views

1 Answer

+11 votes
Best answer
For two points $(x_1,y_1)$ and $(x_2,y_2)$ on a line, Slope of line $= \dfrac{y_2-y_1}{x_2-x_1}$

so ,$\dfrac{q-p}{0-4} = \dfrac{3}{4}$

$\therefore (p-q)=3$

Correct Answer: $C$
by Veteran (57k points)
edited by

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