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2 Answers

Best answer
11 votes
11 votes
Sample space is $S :\{\text{Monday-Tuesday, Tuesday-Wednesday, Wednesday-Thursday}\ldots \text{Sunday-Monday}\}$
Number of elements in $S = n(S) = 7$
What we want is a set $A$ (say) that comprises of the elements $\text{Saturday-Sunday and Friday-Saturday}$
Number of elements in set $A = n(A) = 2$
By definition, probability of occurrence of $A =\dfrac{n(A)}{n(S)} = {2}/{7}$

Therefore, probability that a leap year has $53$ Saturdays is $\dfrac{2}{7}.$

Correct Answer: $A$
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13 votes
13 votes
I think there is  another way .

Since it is leap year .. number of days  = 366

we have 52 weeks in a year .. 52 x 7 = 364

therefore we have already had 52 Saturdays  in these 364 days .. now probability For 53 Saturdays ,

=number of remaining days / number of days in a week = 2/7

the same can be applied to any day of the week .
Answer:

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