Let $a$ be the first odd number.
So the terms of sequence will be
$a, a+2, a+4, a+6, \dots, a+20, a+22$
Sum of first $5$ terms $= a + a+2 + a+4 + a+6 + a+8 = 5a+20 = 425$
We get, $5a = 405$
$\quad \implies a = 81$
Sum of last $5$ terms $= a+22 + a+20 + a+18 + a+16 + a+14$
$\quad \quad \quad = 5a + 90$
Now, we have $a = 81.$ Substituting it we get,
Answer as $5\times 81 + 90 = 405 + 90 = 495$
Answer: 495