2 votes 2 votes Find the odd one from the following group: $W,E,K,O \qquad I,Q,W,A\qquad F,N,T,X\qquad N,V,B,D$ $W,E,K,O$ $I,Q,W,A $ $F,N,T,X $ $N,V,B,D$ Analytical Aptitude gate2014-ec-1 odd-one normal + – makhdoom ghaya asked Mar 18, 2016 makhdoom ghaya 2.7k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 9 votes 9 votes Ans is (D) the no of alphabet between B,D in N,V,B,D is 1 while in other 3 sets, it is 4. Alphabet sequence in all the sets are obtained by adding 8,6,4 respectively to the previous one in sequence. srestha answered Mar 18, 2016 • selected Mar 19, 2016 by Praveen Saini srestha comment Share Follow See 1 comment See all 1 1 comment reply Prateek pallaw commented Sep 13, 2022 i edited by Prateek pallaw Sep 13, 2022 reply Follow Share alphabet between B, and D is 1 while in the other 3 sets it is 3 (i think correction is required in the above solution)and how we are getting “Alphabet sequence in all the sets by adding 8,6,4 respectively to the previous one in sequence.” I don't understand.@srestha 0 votes 0 votes Please log in or register to add a comment.
3 votes 3 votes W E K O -> W E (+6=NEXT Digit) K O I Q W A -> I Q (+6=NEXT Digit) W A F N TX -> F N (+6 =NEXT Digit) T X N V B D -> N V (-20=NEXT Digit) B D option "D" only odd one Prateek kumar answered Sep 25, 2016 Prateek kumar comment Share Follow See all 0 reply Please log in or register to add a comment.