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You are given three coins: one has heads on both faces, the second has tails on both faces, and the third has a head on one face and a tail on the other. You choose a coin at random and toss it, and it comes up heads. The probability that the other face is tails is

  1. $\dfrac{1}{4}$ 
  2. $\dfrac{1}{3}$ 
  3. $\dfrac{1}{2}$ 
  4. $\dfrac{2}{3}$ 
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ans is option B.1/3
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B. 1/3 . Only one coin has the head on one face and tail on another and we can select one coin from 3 coins in 3 ways.

So, probability is favorable cases (one in this case) divided by total cases i.e 3.
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This illustration may help and note here we have equal probablity for choosing fair, unfair H & T coin as 1/3 each.

Answer:

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