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The sum of eight consecutive odd numbers is $656$. The average of four consecutive even numbers is $87$. What is the sum of the smallest odd number and second largest even number?
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Let the eight consecutive odd numbers be $n,n+2,n+4,n+6,n+8,n+10,n+12\;\text{and}\;n+14$
Sum of these numbers is $656, \implies 8n+56=656 , \; \text{so,}\; n= 75.$

Let the four consecutive even numbers be $m,m+2,m+4,\;\text{and}\;m+6$

Average of these numbers is $87, \implies \dfrac{(4m+12)}{4}=87 , \; \text{so,}\; m= 84$

Sum of  smallest odd number and second largest even number is $n + (m+4)= 75+88=163$

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