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Which combination of the integer variables $x, y$ and $z$ makes the variable $a$ get the value $4$ in the following expression?

$$a=(x > y)?((x > z) ?x:z): ((y > z) ?y:z)$$

1. $x=3, y=4, z=2$
2. $x=6, y=5, z=3$
3. $x=6, y=3, z=5$
4. $x=5, y=4, z=5$

edited by

Note:   " ?  : " operator associativity is Right to Left.
Only Assignment, Unary &  ?:  operator are right to left.
Rest all are left to right.

( ) has highest precedence

in above ques , ( ) comes into picture so associativity of ? : not counted
Yes,  here due to bracket, we need not care about the associativity of   ? :   But when there are multiple ?:  & no bracket is there then we should follow right to left.
edited by
Option B and C could be rejected directly because non of the variable X, Y or Z has value 4.
Expression includes only comparison operator $>$, a will take value from x,y,z. That's why option B) and C) can be eliminated.

Check for option A) and D).... option A) satisfy

Option A: 4

Option B: 6

Option C: 6

Option D: 5

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Using option (A) : $x=3, y=4, z=2$

$a=(3>4)?$ No

therefore don't evaluate the first part and check second part $((y>z)?y:z)$

$(4>2)?$ Yes

$a=$ value of $y =4$

Answer is (A) $x=3, y=4, z=2$

by

Given expression finds maximum among x,y and z and assigns it to a.
edited
Yes it is finding maximum between X,Y and Z and assign it to "A"..
Yes , correct @sachin

convert to if-else

if(x>y)

{ if(x>z) a=x;

else a=z;

}

else{

if(y>z) a=y;

else a=z;

}

option:-

 x y z a 3 4 2 4 6 5 3 6 6 3 5 6 5 4 5 5

thanks

The given expression actually finds the max. of 3 integers.
Therefore, the correct option is the one with 4 as the max value.
Therefore, correct opt: (A)