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+4 votes
a = 1+1+1+ 1+1+1 1+1;

as far as i think, it will pass the lexical phase.. it should b syntax error.. correct ??
asked in Compiler Design by (89 points) | 329 views
yes.. All are valid tokens.
Tokens r valid, but d code will not compile. I think d error will b in syntax analyzer phase.. No grammar will b available to construct parse tree of given string.

2 Answers

+8 votes
Best answer

Yes, It will pass the lexical phase. 

There is a specific rule in "integer constant creation" that you can not have a blank space between a number.

In the above line after 5th 1, "1 1", cause an error.  This error is a grammatical error. Hence It will be not pass syntax analysis. Hence syntax error will be generated and reported at compile time. 

answered by Veteran (35.7k points)
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In Lexical analysis phase, it removes all the white spaces and comments. so white space between 1 should also be removed, also LA phase makes use of Regular expressions to identify tokens, so it makes sense what you are saying.

Still confusing.

I think there are conflicts between answers. If there is any example of such question over internet or any other text book you guys know, then please do share.


There is a specific rule in "integer constant creation" that you can not have a blank space between a number


Thanks.. this solved the confusion.
@Arjun Sir, Is my answer is not correct? Why did I get a down vote for this? :( :(
yes, its not correct. 1 1 should be two valid tokens in C.
@Arjun sir, yeah i got my mistake. Now I have edited it. I think now its correct. Thx.
+1 vote
Yes , this error will be generated at the time of syntax analyzer . you cant make a parse tree for this
answered by (23 points)

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