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The Newton-Raphson iteration $x_{n+1} = \frac{1}{2}\left(x_n+\frac{R}{x_n}\right)$ can be used to compute the

  1. square of R      
  2. reciprocal of R      
  3. square root of R      
  4. logarithm of R
in Numerical Methods by
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Best answer

The given expression can be rewritten as,

xn+1 = xn - (xn2 -R)/2xn

therefore, it computes the square root R.
answer (C) is correct.

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