1 votes 1 votes The Newton-Raphson iteration $x_{n+1} = \frac{1}{2}\left(x_n+\frac{R}{x_n}\right)$ can be used to compute the square of R reciprocal of R square root of R logarithm of R Numerical Methods gatecse-2008 newton-raphson normal numerical-methods out-of-syllabus-now + – Kathleen asked Sep 11, 2014 retagged Dec 21, 2017 by Rupendra Choudhary Kathleen 5.2k views answer comment Share Follow See 1 comment See all 1 1 comment reply akash.dinkar12 commented Aug 6, 2018 reply Follow Share See this... 0 votes 0 votes Please log in or register to add a comment.
Best answer 3 votes 3 votes The given expression can be rewritten as, xn+1 = xn - (xn2 -R)/2xn therefore, it computes the square root R. answer (C) is correct. suraj answered Sep 12, 2014 selected Jul 25, 2015 by Arjun suraj comment Share Follow See all 0 reply Please log in or register to add a comment.