That's true. P is adding the first k odd numbers and Q is adding the first k even numbers. Each even number is 1 greater than its corresponding odd number being added. So for k additions, Q will be P+k

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## 7 Answers

### 5 Comments

Try to use substitution method here

Let k=2

We know that 1<= i <= 2k

That is 1<=i<= 4

For P i is odd

For Q i is even

Therefore P will be 1+3 => 4

Q will be 2+4 =>6

Now check options and substitute values of P , Q ,k in options

a) P = Q-k

4 = 6-2

4=4

b) P=Q+k

4 = 6+2

4 != 8

c) P=Q

4!= 6

d) P=Q+2k

4 = 6+2(2)

4!= 10

Only option a) is satisfying

**Therefore correct answer is option A**