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Aishwarya studies either computer science or mathematics everyday. If she studies computer science on a day, then the probability that she studies mathematics the next day is $0.6$. If she studies mathematics on a day, then the probability that she studies computer science the next day is $0.4$. Given that Aishwarya studies computer science on Monday, what is the probability that she studies computer science on Wednesday?

1. $0.24$
2. $0.36$
3. $0.4$
4. $0.6$
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on Wednesday we want cs required probability = $0.6 \times 0.4 + 0.4 \times 0.4 = 0.4$

selected by

prob of studying CS on Tue = 0.4

prob of studying CS on Wed given that it was studied on Tue = 0.4 x 0.4 = 0.16

prob of studying Math on Tue = 0.6

prob of studying CS on Wed given that Math was studied on Tue = 0.6 x 0.4 = 0.24

prob = 0.16 + 0.24 = 0.4
I think both the events are independent events bcoz the prob she studies cs any particular day is .4 and she studies Maths any particular day is  .6 .

Given that she study cs on Mon then,∣

prob(Cs on Wed) = P(Cs on Tue , Cs on Wed) +P(Maths on Tue,Cs on Wed)

=P(Cs on Tue).P(Cs on Wed)+P(Maths on Tue).P(Cs on Wed)

=.4*.4 +.6*.4 =.4

In short, prob(Cs on Wed ∣ Cs on Mon ) = prob(Cs on Wed) = .4      // Independent
+1 vote

Given that Aishwarya studied CS on Monday,so possible scenarios are-:

$\text{MON TUE WED}$

$\text{1.CS MATHS MATHS}$

$\text{2.CS MATHS CS}$

$\text{3.CS CS MATHS}$

$\text{4.CS CS CS}$

case $1$ and $3$ will be discarded as the question is asking the probability that she studies computer science on Wednesday

Given that

• $\text{CS} \rightarrow \text{MATHS}=0.6$
• $\text{MATHS} \rightarrow CS=0.4$
• $\text{CS} \rightarrow \text{CS} =0.4$
• $\text{Maths} \rightarrow \text{Maths} =0.6$

Considering Case $2$ and $4$ we need to find their respective probability.

case $2 -: 0.6 \times 0.4$

case $4-: 0.4 \times 0.4$

Required proabaility=$0.24+.16=0.4$