The Gateway to Computer Science Excellence
First time here? Checkout the FAQ!
x
+10 votes
822 views

Consider the following recursive C function that takes two arguments.

unsigned int foo(unsigned int n, unsigned int r) {
    if (n>0) return ((n%r) + foo(n/r, r));
    else return 0;
}

What is the return value of the function $\text{foo}$ when it is called as $\text{foo(513, 2)}$?

  1. $9$
  2. $8$
  3. $5$
  4. $2$
asked in Algorithms by Veteran (103k points)
edited by | 822 views

2 Answers

+16 votes
Best answer
The function returns the sum of digits in a binary representation of the given number

so $1+0+0+0+0+0+0+0+0+1 = 2$
answered by Loyal (7.6k points)
edited by
0
if you simulate this program with different values of n and r, notice that this function foo(n,r) gives the sum of digits of n(when it is converted to base r).

Like if n=513, r=14 then $(513)_{10}=(289)_{14}$ and 2+8+9=19 and this is the output of the program.
+8 votes

Final return value is 2 So option d

answered by Boss (38.8k points)


Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true

40,733 questions
47,461 answers
145,525 comments
62,224 users