0 votes 0 votes ww^r complement is CSL Is this right or wrong If right please how can we prove Theory of Computation made-easy-test-series theory-of-computation identify-class-language + – Sourabh Kumar asked Apr 23, 2016 • edited Mar 5, 2019 by akash.dinkar12 Sourabh Kumar 737 views answer comment Share Follow See 1 comment See all 1 1 comment reply ManojK commented Apr 23, 2016 reply Follow Share @Praveen Sir can you check this qus.How to find complement ww^r.what will the language after finding complement. 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes Correct wwr is CFL . CFl not closed under complement so move up to chomsky hirarchy . since every CFL is CSL and Compliment of CSL is CSL. Prashant. answered Apr 23, 2016 Prashant. comment Share Follow See all 3 Comments See all 3 3 Comments reply ManojK commented Apr 23, 2016 reply Follow Share But here ww^r is language Complement is ∑*-(WW^r) so it be CFL hence CSL too 0 votes 0 votes Prashant. commented Apr 23, 2016 reply Follow Share So what Complement never be above CSL . 0 votes 0 votes ManojK commented Apr 23, 2016 reply Follow Share WW^R complement =CFL or not?? 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes $WW^{r}$ complement is either an "odd length string" or "even length string xy such that $x^{r} != y$". Because of 2nd requirement it is CFL because we can check for all string xy such that $x^{r} != y$ reboot answered Dec 27, 2020 reboot comment Share Follow See all 0 reply Please log in or register to add a comment.