GATE CSE
First time here? Checkout the FAQ!
x
+10 votes
1.1k views

A sub-sequence of a given sequence is just the given sequence with some elements (possibly none or all) left out. We are given two sequences $X[m]$ and $Y[n]$ of lengths m and n, respectively with indexes of $X$ and $Y$ starting from $0$.

We wish to find the length of the longest common sub-sequence (LCS) of $X[m]$ and $Y[n]$ as $l(m, n)$, where an incomplete recursive definition for the function $I(i, j)$ to compute the length of the LCS of $X[m]$ and $Y[n]$ is given below:

$l(i,j)  = 0$, if either i = 0 or j = 0
        = expr1, if i,j > 0 and X[i-1] = Y[j-1]
        = expr2, if i,j > 0 and X[i-1] ≠ Y[j-1]
The value of $l(i,j)$ could be obtained by dynamic programming based on the correct recursive definition of $l(i,j)$ of the form given above, using an array $L[M,N]$, where $M = m+1$ and $N = n+1$, such that $L[i, j] = l(i, j)$.

Which one of the following statements would be TRUE regarding the dynamic programming solution for the recursive definition of $l(i, j)$?

  1. All elements of $L$ should be initialized to 0 for the values of $l(i, j)$ to be properly computed.
  2. The values of $l(i, j)$ may be computed in a row major order or column major order of $L[M, N]$.
  3. The values of $l(i, j)$ cannot be computed in either row major order or column major order of $L[M, N]$.
  4. $L[p, q]$ needs to be computed before $L[r, s]$ if either $p<r$ or $q < s$.
asked in Algorithms by Veteran (92.5k points) 972 2329 3115 | 1.1k views

2 Answers

+16 votes
Best answer

$\text{expr2} = \max\left(l\left(i-1, j\right), l\left(i,j-1\right)\right)$

When the currently compared elements doesn't match, we have two possibilities for the LCS, one including X[i] but not Y[j] and other including Y[j] but not X[i].

/* Returns length of LCS for X[0..m-1], Y[0..n-1] */
int lcs( char *X, char *Y, int m, int n )
{
   if (m == 0 || n == 0)
     return 0;
   if (X[m-1] == Y[n-1])
     return 1 + lcs(X, Y, m-1, n-1);
   else
     return max(lcs(X, Y, m, n-1), lcs(X, Y, m-1, n));
}

54. Answer is B. Dynamic programming is used to save the previously found LCS. So, for any index [p,q] all smaller ones should have been computed earlier. Option D is not correct as the condition given requires even L[3,2] to be computed before L[2,4] which is not a necessity if we follow row-major order. 

int lcs( char *X, char *Y, int m, int n )
{
   int L[m+1][n+1];
   int i, j;
  
   /* Following steps build L[m+1][n+1] in bottom up fashion. Note 
      that L[i][j] contains length of LCS of X[0..i-1] and Y[0..j-1] */
   for (i=0; i<=m; i++)
   {
     for (j=0; j<=n; j++)
     {
       if (i == 0 || j == 0)
         L[i][j] = 0;
  
       else if (X[i-1] == Y[j-1])
         L[i][j] = L[i-1][j-1] + 1;
  
       else
         L[i][j] = max(L[i-1][j], L[i][j-1]);
     }
   }
    
   /* L[m][n] contains length of LCS for X[0..n-1] and Y[0..m-1] */
   return L[m][n];
}

 

answered by Veteran (319k points) 577 1447 2962
selected by
Q.54

Suppose

X=abcba

Y=bcaba

Problem with tracing code.

When i=j=0.

and i=0 and j=1

Plz Help Me here _/\_

@Rajesh
Here L[i-1][j] is for row major order, and L[i][j-1] for column major order
X=abcba
Y=bcaba
i=0,j=0 will be matching  a $\neq$ b[a from 1st string, b from 2nd string]
 i=0 and j=1be a$\neq$c
 
but here the code will be
 

for (i=0; i<=m; i++)
   {
     for (j=i; j<=n; j++)
     {


na?

sir not able to understand options D@ arjun sir
+12 votes

$\text{expr2} = \max\left(l\left(i-1, j\right), l\left(i,j-1\right)\right)$

When the currently compared elements doesn't match, we have two possibilities for the LCS, one including X[i] but not Y[j] and other including Y[j] but not X[i].

Answer is B. We can either use Row Major or column major order.

Issue of option D -> Read option D carefully.

L[p,q] needs to be computed before L[r,s] if either p < q or r < s

 Assuming that we want to compute L(3,3). We need not compute L(4,2) if we are using Row Major Order ! Here L(4,2) = L[p,q] & L(3,3) = L[r,s]. Then q<s still we need not compute it ! so D IS FALSE

answered by Veteran (45.7k points) 171 533 843
Can you elaborate on last paragraph of the answer.
i think option D should also be correct  because to compute l[3,3] we need L[2,3]  or L[3,2] or L[2,2].
he wrote wrong condition , in question its p<r, or q<s,

now he is trying to say , if i want to value of l[3,3] means l[r,s] , then it needs to compute , l[p,s] means l[2,3], l[2,2], l[3,2] for these no problem but ,l[4,2](q,s) which satisfied condition but it will compute after l[33] in row major oder ,,

thats why d is false ...


Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true
Top Users Oct 2017
  1. Arjun

    23398 Points

  2. Bikram

    17078 Points

  3. Habibkhan

    8264 Points

  4. srestha

    6296 Points

  5. Debashish Deka

    5438 Points

  6. jothee

    4978 Points

  7. Sachin Mittal 1

    4772 Points

  8. joshi_nitish

    4348 Points

  9. sushmita

    3966 Points

  10. Rishi yadav

    3804 Points


Recent Badges

Famous Question im.raj
Verified Human gk
Notable Question Sanjay Sharma
Popular Question Pravin Paikrao
Notable Question Sanjay Sharma
Notable Question Vineeta
Popular Question rahul sharma 5
Famous Question rahuldb
Great Question jothee
Notable Question Vaishali Trivedi
27,324 questions
35,176 answers
84,111 comments
33,280 users